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Sahay Sir > Question Answers > Cengage JEE Mains Physics by B.M Sharma > Chapter 6 - Newton's Laws of Motion (With Friction) and Dynamics of Circular Motion > A solid block of mass 2kg is resting inside a cube shown in figure The cube is moving with a velocity vˆ=5iˆ+2jˆms^−1 If the coefficient of friction between the surface of cube and block is 0.2 then the force of friction between the block and cube is

A solid block of mass 2kg is resting inside a cube shown in figure The cube is moving with a velocity vˆ=5iˆ+2jˆms^−1 If the coefficient of friction between the surface of cube and block is 0.2 then the force of friction between the block and cube is

A block of mass m if coefficient of friction between the block and the surface is inclined at an angle θ to the vertical. The block will remain in equilibrium lying on a rough horizontal plane is acted upon by a horizontal force P and another force Q