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Sahay Sir > Question Answers > Cengage JEE Mains Physics by B.M Sharma > Chapter 6 - Newton's Laws of Motion (With Friction) and Dynamics of Circular Motion > A small ring P is threaded on a smooth wire bent in the form of a circle of radius a and center O. The wire is rotating with constant angular speed ω about a vertical diameter XY while the ring remains at rest relative to the wire at a distance a/2 from XY. Then ω^2 is equal to

A small ring P is threaded on a smooth wire bent in the form of a circle of radius a and center O. The wire is rotating with constant angular speed ω about a vertical diameter XY while the ring remains at rest relative to the wire at a distance a/2 from XY. Then ω^2 is equal to

as shown .If F1 is removed F2=2N Figure shown a wooden block at rest in equilibrium on a rough horizontal plane being acted upon by force F1=10N the resulting force acting on the block will be