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Sahay Sir > Question Answers > Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) > A small block of mass 4 kg is attached to a cord passing through in a horizontal frictionless surface. The block is originally revolving in a circle of radius 0.5 m about the hole with a tangential velocity of 4 m/s. The cord is then pulled slowely from below shortening the radius of the circle in which the block revolves. The breaking strength of the cord is 600 N. What will be the radius of the circle when the cord breaks?

A small block of mass 4 kg is attached to a cord passing through in a horizontal frictionless surface. The block is originally revolving in a circle of radius 0.5 m about the hole with a tangential velocity of 4 m/s. The cord is then pulled slowely from below shortening the radius of the circle in which the block revolves. The breaking strength of the cord is 600 N. What will be the radius of the circle when the cord breaks?

A disk with moment of inertia I1 rotates about a frictionless drops onto the first disk. Because of friction between the surfaces the two eventually reach the same angular speed ω f. Calculate ω f. this one having moment of inertia I2 and initially not rotating vertical axle with angular speed ω i. A second disk