A simple pendulum performs simple harmonic motion about x=0 with an amplitude ′a′ and time period ′T′. The speed of the pendulum at x = 2/a will be: A simple pendulum performs simple harmonic motion about x=0 with an amplitude ′a′ and time period ′T′. The speed of the pendulum at x = 2/a will be: August 31, 2020 Category: Chapter 15 - SHM , NEET Last 32 Years Solved 1988 - 2019 Physics and Chemistry Video Solutions , Physics , Facebook Messenger WhatsApp Share this:TwitterFacebook Related A simple pendulum performs simple harmonic motion about x = 0 with an amplitude ′ a ′ and time period ′ T ′. The speed of the pendulum at x = 2/a will be:A simple pendulum performs simple harmonic motion about x = 0 with an amplitude ′ a ′ and time period ′ T ′. The speed of the pendulum at x = 2/a will be:A vehicle is moving on a circular path of radius R with constant speed sqrt(gR). A simple pendulum of length l hangs from the ceilling of the vehicle. The time period of oscillations of the pendulum is
