A simple pendulum performs simple harmonic motion about x=0 with an amplitude ′a′ and time period ′T′. The speed of the pendulum at x = 2/a will be: A simple pendulum performs simple harmonic motion about x=0 with an amplitude ′a′ and time period ′T′. The speed of the pendulum at x = 2/a will be: August 31, 2020 Category: Chapter 15 - SHM , NEET Last 32 Years Solved 1988 - 2019 Physics and Chemistry Video Solutions , Physics , Facebook Messenger WhatsApp Share this:TwitterFacebook Related
