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Sahay Sir > Question Answers > JEE Mains Physics 2002-2019 Solved Video Solutions > Chapter 10 - Oscillation and Waves > A simple harmonic motion is represented by: y = 5 (sin 3πt+ 3–√ cos 3πt) cm The amplitude and time period of the motion are:

A simple harmonic motion is represented by: y = 5 (sin 3πt+ 3–√ cos 3πt) cm The amplitude and time period of the motion are:

November 6, 2020
Category: Chapter 10 - Oscillation and Waves , JEE Mains Physics 2002-2019 Solved Video Solutions ,

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