A signal of 0.1 kW is transmitted in a cable. The attenuation of cable is –5 dB per km and cable length is 20 km. The power received at receiver is 10^–x W. The value of x is …… [Gain in dB = 10 log10 (P0/Pi)] The logic circuit shown above is equivalent to : September 26, 2021 Category: JEE Mains Physics 2002-2019 Solved Video Solutions , Practice Set 1 , Facebook Messenger WhatsApp Share this:TwitterFacebook Related