A ship A is moving Westwards with a speed of 10 km h^−1 and a ship B 100 km South of A is moving northwards with a speed of 10 km h^−1. The time after which the distance between them becomes shortest is The x and y coordinates of the particle at any time are x=5t − 2t^2 and y = 10t respectively where x and y are in meters and t in seconds. The acceleration of the particle at t = 2 s is: August 28, 2020 Category: Chapter 4 - Motion in a Plane , NEET Last 32 Years Solved 1988 - 2019 Physics and Chemistry Video Solutions , Physics , Facebook Messenger WhatsApp Share this:TwitterFacebook Related