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Sahay Sir > Question Answers > Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) > A semicircular disc of rtadius R and mass M is pulled by a horizontal force F so that it moves with uniform velocity.The coefficient frictoin between disc and ground is mu = 4 / 3 pie. Find the value of theta in degree.

A semicircular disc of rtadius R and mass M is pulled by a horizontal force F so that it moves with uniform velocity.The coefficient frictoin between disc and ground is mu = 4 / 3 pie. Find the value of theta in degree.

Two rods each of mass m = 4 kg and length l = 1 m are in equilibrium being smoothly hinged at P. Find the tension in the connecting string as shown in figure.