A saturated solution of Ca3 (PO4)2 has [Ca^2+ ] = 2×10^−8 M and [PO 4/3 – ]=1.6×10^−5 M of Ksp of Ca^3 (PO^4 )2 is : A saturated solution of Ca3 (PO4)2 has [Ca^2+ ] = 2×10^−8 M and [PO 4/3 - ]=1.6×10^−5 M of Ksp of Ca^3 (PO^4 )2 is : November 17, 2020 Category: Chapter 6 - Ionic Equilibrium (Level 1 and Level 2) , Chapter 7 - Equilibrium , N Awasthi Physical Chemistry , Facebook Messenger WhatsApp Share this:TwitterFacebook Related
