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Sahay Sir > Question Answers > JEE Mains Physics 2002-2019 Solved Video Solutions > Practice Set 1 > A rod of length L has non-uniform linear mass density given by ρ(x) = a + b(x/L)^2, where a and b are constants and 0 ≤ x ≤ L. The value of x for the centre of mass of the rod is at

A rod of length L has non-uniform linear mass density given by ρ(x) = a + b(x/L)^2, where a and b are constants and 0 ≤ x ≤ L. The value of x for the centre of mass of the rod is at

A rod of length L has non-uniform linear mass density given by ρ(x) = a + b(x/L)^2 where a and b are constants and 0 ≤ x ≤ L. The value of x for the centre of mass of the rod is at