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Sahay Sir > Question Answers > Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) > A ring of mass m = 10 kg can slide through a vertical rod with friction. It is connected with a spring of force constant k = 100 N/m. The relaxed length of spring is 4 m. The ring is displaced 3 m as shown

A ring of mass m = 10 kg can slide through a vertical rod with friction. It is connected with a spring of force constant k = 100 N/m. The relaxed length of spring is 4 m. The ring is displaced 3 m as shown

A block of mass m is released from point (A) in Figure. The track is frictionless except for the portion between points (B) and (C) which has a length of dBC. The block travels down the track