A remote – sensing satellite of earth revolves in a circular orbit at a height of 0.25 × 10^6 m above the surface of earth. If earth’s radius is 6.38 × 10^6 m and g = 9.8ms^−2, then the orbital speed of the satellite is: A remote - sensing satellite of earth revolves in a circular orbit at a height of 0.25 × 10^6 m above the surface of earth. If earth's radius is 6.38 × 10^6 m and g = 9.8ms^−2 then the orbital speed of the satellite is: August 29, 2020 Category: Chapter 12 - Gravitation , NEET Last 32 Years Solved 1988 - 2019 Physics and Chemistry Video Solutions , Physics , Facebook Messenger WhatsApp Share this:TwitterFacebook Related A satellite is revolving in a circular orbit at a height 'h' from the earth's surface (radius of earth R, h ltltR). The minimum increase in its orbital velocity required, So that the satellite could escape from the erth's gravitational field, is close to :(Neglect the effect of atomsphere.)A satellite of mass m revolves around the earth of radius R at a height x from its surface. If g is the acceleration due to gravity on the surface of the earth, the orbital speed of the satellite isThe orbital velocity of an artificial satellite in a circular orbit just above the earth's surface is V 0 . The orbital velocity of a satellite orbiting at an altitude of half of the radius, is:
