Question Answers

Sahay Sir > Question Answers > Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) > A rectangular bar is fixed to a hard floor. Height of the bar is h and its area in contact with the floor is A. A shearing force distorts the bar as shown. Prove that the work done by the shearing force is W=(σ22η)× volume of the bar. Here σ is shear modulus of elasticity. Assume the deformation to be small.

A rectangular bar is fixed to a hard floor. Height of the bar is h and its area in contact with the floor is A. A shearing force distorts the bar as shown. Prove that the work done by the shearing force is W=(σ22η)× volume of the bar. Here σ is shear modulus of elasticity. Assume the deformation to be small.

A steel ring of radius r and cross section area A is fitted on to a wooden disc of radius R(R>r). If Young's modulus be R Search Results Featured snippet from the web Image result for two bars A and B are stuck using an adhesive then the force with which the steel ring is expanded is