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Sahay Sir > Question Answers > Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) > A proton of mass 1.67 x 10^ -27 kg and charge 1.67 x 10^-19 C is projected with a speed of 2 x 10^6 m/s at an angle of 60 degree to the X – axis. If a uniform magnetic field of 0.10 T is applied along Y – axis , the path of proton is

A proton of mass 1.67 x 10^ -27 kg and charge 1.67 x 10^-19 C is projected with a speed of 2 x 10^6 m/s at an angle of 60 degree to the X – axis. If a uniform magnetic field of 0.10 T is applied along Y – axis , the path of proton is

A charged particle moving along positive x-direction with a velocity v enters a region where there is a uniform magnetic field B =−B k ^ from x=0 to x=d.The particle gets deflected at an angle θ from its initial path.The specific charge of the particle is