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Sahay Sir > Question Answers > Arihant Physics by D.C Pandey > Volume 2 > Chapter 2 - Electrostatic Potential and Capacitance > A potential difference of 500V is applied to a parallel plate condenser. The separation between plates is 2×10^−3 m. The plates of the condenser are vertical. An electron is projected vertically upwards between the plates with a velocity of 10^5 m/s and it moves undeflected between the plates. The magnetic field acting perpendicular to the electric field has a magnitude of.

A potential difference of 500V is applied to a parallel plate condenser. The separation between plates is 2×10^−3 m. The plates of the condenser are vertical. An electron is projected vertically upwards between the plates with a velocity of 10^5 m/s and it moves undeflected between the plates. The magnetic field acting perpendicular to the electric field has a magnitude of.

In the given circuit potential of point A is :