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Sahay Sir > Question Answers > Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) > A positively charged particle starts at rest 25 cm from a second positively charged particle, which is held stationary throughout the experiment. The first particle is released and accelerates directly away from the second particle. When the first particle has moved 25 cm, it has reached a velocity of 10(2–√)ms−1 . What is the maximum velocity (∈×10 m/s) that the first particle will reach?

A positively charged particle starts at rest 25 cm from a second positively charged particle, which is held stationary throughout the experiment. The first particle is released and accelerates directly away from the second particle. When the first particle has moved 25 cm, it has reached a velocity of 10(2–√)ms−1 . What is the maximum velocity (∈×10 m/s) that the first particle will reach?

A positively charged particle starts at rest 25 cm from a second positively charged particle it has reached a velocity of 10(2–√)ms−1 . What is the maximum velocity (∈×10ms−1) that the first particle will reach? which is held stationary throughout the experiment. The first particle is released and accelerates directly away from the second particle. When the first particle has moved 25 cm