A position dependent force F= 7 − 2x + 3x^2 newton (where x is in meter) on a small body of mass 2 Kg & displace it from x = 0 to x = 5 m. Work done in joule is A position dependent force F= 7 − 2x + 3x^2 newton (where x is in meter) on a small body of mass 2 Kg & displace it from x = 0 to x = 5 m. Work done in joule is August 24, 2020 Category: Chapter 7 - Work, Energy and Power , NEET Last 32 Years Solved 1988 - 2019 Physics and Chemistry Video Solutions , Physics , Facebook Messenger WhatsApp Share this:TwitterFacebook Related