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Sahay Sir > Question Answers > Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) > A particular type of nucleus whose decay constant is lambda is produced at a steady rate of p nuclei per second. Show that the number of nuclei N present t second after the production starts is N=(P)/(lambda)[1-e^(~lambdat)].

A particular type of nucleus whose decay constant is lambda is produced at a steady rate of p nuclei per second. Show that the number of nuclei N present t second after the production starts is N=(P)/(lambda)[1-e^(~lambdat)].

A gas hydrogen like atoms can absorb radiations of 68eV. Consequently A is ahead of B in phase by 66^@. If the observation be taken from point P Among the two interfering monochromatic sources A and B such that PB-PA=lambda//4. Then the phase difference between the waves from A and B reaching P is