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Sahay Sir > Question Answers > Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) > A particle with charge – 5.60 nC is moving in a uniform magnetic field → B = − ( 1.25 T ) ^ k . The magnetic force on the particle Is measured to be → F = − ( 3.36 × 10^ − 7 N ) ^ i + ( 7.42 × 10^ − 7 N ) ^ j . (a) Calculate the x-component of the velocity of the particle. (b) Calculate the y-component of the velocity of the particle. (c) Calculate the scalar product → v ⋅ → F .

A particle with charge – 5.60 nC is moving in a uniform magnetic field → B = − ( 1.25 T ) ^ k . The magnetic force on the particle Is measured to be → F = − ( 3.36 × 10^ − 7 N ) ^ i + ( 7.42 × 10^ − 7 N ) ^ j . (a) Calculate the x-component of the velocity of the particle. (b) Calculate the y-component of the velocity of the particle. (c) Calculate the scalar product → v ⋅ → F .

A charged particle has acceleration a vector = 2i^ + xj^ in a magnetic field B Vector= -3i^ +2 j^ -4k^. Find the value of x