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Sahay Sir > Question Answers > Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) > A particle slides with a speed of 3ms ^ −1 . When it reaches Q, it acquires a speed of 4ms −1 after describing an angle of 60 o at O as shown in Figure. Find the change in the velocity of the particle between P and Q. Assume that the path followed by the particle is circular from P to Q.

A particle slides with a speed of 3ms ^ −1 . When it reaches Q, it acquires a speed of 4ms −1 after describing an angle of 60 o at O as shown in Figure. Find the change in the velocity of the particle between P and Q. Assume that the path followed by the particle is circular from P to Q.

A particle slides with a speed of 3ms −1 . When it reaches Q The resultant of two forces P and Q is R If Q is doubled and when Q is reversed R is again doubled. Show that P:Q:R= 2 ​ : 3 ​ : 2