A particle of unit mass undergoes one-dimensional motion such that its velocity varies according to v(x) = βx − 2n, where β and n are constants and x is the position of the particle. The acceleration of the particle as a function of x, is given by A particle of unit mass undergoes one-dimensional motion such that its velocity varies according to v(x) = βx − 2n is given by where β and n are constants and x is the position of the particle. The acceleration of the particle as a function of x August 27, 2020 Category: Chapter 3 - Motion in a Straight Line , NEET Last 32 Years Solved 1988 - 2019 Physics and Chemistry Video Solutions , Physics , Facebook Messenger WhatsApp Share this:TwitterFacebook Related