A particle of unit mass undergoes one-dimensional motion such that its velocity varies according to v(x) = βx − 2n, where β and n are constants and x is the position of the particle. The acceleration of the particle as a function of x, is given by A particle of unit mass undergoes one-dimensional motion such that its velocity varies according to v(x) = βx − 2n is given by where β and n are constants and x is the position of the particle. The acceleration of the particle as a function of x August 27, 2020 Category: Chapter 3 - Motion in a Straight Line , NEET Last 32 Years Solved 1988 - 2019 Physics and Chemistry Video Solutions , Physics , Facebook Messenger WhatsApp Share this:TwitterFacebook Related The displacement x of a particle varies with time t as x = ae^−αt + be^βt, Where a, b, α and β are positive constants. The velocity of the particle will:The distance x covered by a particle in one dimensional motion varies with time t as x^2 = at^2 + 2bt + c. If the acceleration of the particle depends on x as x^–n, where n is an integer, the value of n is __________ .The displacement x of a particle varies with time t as x = ae^ − αt + be^βt. Where a, b, α and β positive constant. The velocity of the particle will