Question Answers

Sahay Sir > Question Answers > Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) > A particle of mass m=0.1kg and having positive charge q=75μC is suspended from a point by a thread of length l=10cm. In the space, a uniform horizontal electric field E=104NC−1 exists. The particle is drawn aside so that the thread becomes vertical and then it is projected horizontally with velocity v such that the particle starts to move along a circle with the same constant speed V. Calculate the radius of the circle and speed v(g=10 ms^−2).

A particle of mass m=0.1kg and having positive charge q=75μC is suspended from a point by a thread of length l=10cm. In the space, a uniform horizontal electric field E=104NC−1 exists. The particle is drawn aside so that the thread becomes vertical and then it is projected horizontally with velocity v such that the particle starts to move along a circle with the same constant speed V. Calculate the radius of the circle and speed v(g=10 ms^−2).

A particle of mass m=0.1kg and having positive charge q=75μC is suspended from a point by a thread of length l=10cm. In the space each of radius r and supported on insulating stands the net electrostatic potential created by these charges is V. Find the separation r between the charges. Two point like charges q1 and q2 are fixed in free space. At every point on the curve shown Two small metal spheres A and B