A particle of mass 2kg moves with an initial velocity of (4iˆ+2jˆ)ms−1 on the x-y plane. A force F→=(2iˆ−8jˆ)N acts on the particle. The initial position of the particle is (2m,3m). Then for y=3m, 3m). Then for y=3m A particle of mass 2kg moves with an initial velocity of (4iˆ+2jˆ)ms−1 on the x-y plane. A force F→=(2iˆ−8jˆ)N acts on the particle. The initial position of the particle is (2m October 19, 2020 Category: Cengage JEE Mains Physics by B.M Sharma , Chapter 5 - Newton's Laws of Motion (Without Friction) , Facebook Messenger WhatsApp Share this:TwitterFacebook Related