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Sahay Sir > Question Answers > Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) > A particle of mass 2 × 10^−5 kg moves horizontally between two horizontal plates of a charged parallel plate capacitor between which there is an electric field of 200 N/C acting upward. A magnetic induction of 2.0 T is applied at right angles to the electric field in a direction normal to both B and v . If g is 9.8 m/s^2 and the charge on the particle is 10^−6 C, then find the velocity of charge particle so that it continues to move horizontally

A particle of mass 2 × 10^−5 kg moves horizontally between two horizontal plates of a charged parallel plate capacitor between which there is an electric field of 200 N/C acting upward. A magnetic induction of 2.0 T is applied at right angles to the electric field in a direction normal to both B and v . If g is 9.8 m/s^2 and the charge on the particle is 10^−6 C, then find the velocity of charge particle so that it continues to move horizontally

An electron is launched with velocity v in a uniform magnetic field B. The angle θ between v and B lies between 0 and π/2. Its velocity vector v returns to its initial value in a time interval of