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Sahay Sir > Question Answers > Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) > A particle of mass 2 m is projected at an angle of 45∘ with horizontal with a velocity of 202 root 2 m/s. After 1 s explosion takes place and the particle is broken into two equal pieces. As a result of explosion one part comes to rest. Find the maximum height attained by the other part. Take g = 10 m/s^2.

A particle of mass 2 m is projected at an angle of 45∘ with horizontal with a velocity of 202 root 2 m/s. After 1 s explosion takes place and the particle is broken into two equal pieces. As a result of explosion one part comes to rest. Find the maximum height attained by the other part. Take g = 10 m/s^2.

An object initially at rest explodes into three fragments A B and C.The momentum of A is piˆ and that of B is 3–√pjˆ where p is a+ve number. The momentum of C will be