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Sahay Sir > Question Answers > Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) > A particle of mass 2 kg moves with an initial velocity of v = 4i + 4j m/s. A constant force of F = 20 j N is applied on the particle. Initially, the particle was at (0,0). The x-coordinate of the particle

A particle of mass 2 kg moves with an initial velocity of v = 4i + 4j m/s. A constant force of F = 20 j N is applied on the particle. Initially, the particle was at (0,0). The x-coordinate of the particle

0). The x-coordinate of the particle A particle of mass 2 kg moves with an initial velocity of v = 4i + 4j m/s. A constant force of F = 20 j N is applied on the particle. Initially the particle was at (0