A particle of mass 2 kg moves with an initial velocity of v = 4i + 4j m/s. A constant force of F = 20 j N is applied on the particle. Initially, the particle was at (0,0). The x-coordinate of the particle

A particle of mass 2kg moves with an initial velocity of v→=4iˆ+4jˆms^−1. A constant force of F→=20jˆN is applied on the particle. Initially, the particle was at (0,0). The x-coordinates of the particle when its y-coordinates again becomes zero is given by

A particle of mass 2 kg moves with an initial velocity of (4i + 2j) m/s on the x-y plane. A force F = (2i - 8j) N acts on the particle. The initial position of the particle is (2m, 3 m).

[vc_row][vc_column][stm_post_info css=".vc_custom_1437111129257{margin-bottom: 0px !important;}"][vc_row_inner][vc_column_inner width="1/6"][/vc_column_inner][vc_column_inner width="1/6"][/vc_column_inner][/vc_row_inner][vc_row_inner][vc_column_inner width="1/6"][/vc_column_inner][vc_column_inner width="2/3"][vc_single_image image="40347" img_size="large"][vc_single_image image="40352" img_size="large"][/vc_column_inner][vc_column_inner width="1/6"][/vc_column_inner][/vc_row_inner][vc_row_inner][vc_column_inner width="1/2"][stm_post_tags][/vc_column_inner][vc_column_inner width="1/2"][stm_share code="JTNDc3BhbiUyMGNsYXNzJTNEJTI3c3RfZmFjZWJvb2tfbGFyZ2UlMjclMjBkaXNwbGF5VGV4dCUzRCUyNyUyNyUzRSUzQyUyRnNwYW4lM0UlMEElM0NzcGFuJTIwY2xhc3MlM0QlMjdzdF90d2l0dGVyX2xhcmdlJTI3JTIwZGlzcGxheVRleHQlM0QlMjclMjclM0UlM0MlMkZzcGFuJTNFJTBBJTNDc3BhbiUyMGNsYXNzJTNEJTI3c3RfZ29vZ2xlcGx1c19sYXJnZSUyNyUyMGRpc3BsYXlUZXh0JTNEJTI3JTI3JTNFJTNDJTJGc3BhbiUzRSUwQSUzQ3NwYW4lMjBjbGFzcyUzRCUyN3N0X3NoYXJldGhpc19sYXJnZSUyNyUyMGRpc3BsYXlUZXh0JTNEJTI3JTI3JTNFJTNDJTJGc3BhbiUzRQ=="][/vc_column_inner][/vc_row_inner][stm_post_author][stm_post_comments][/vc_column][/vc_row]

A uniform force of (3i^+j^​) newton acts on a particle of mass 2 kg. Hence the particle is displaced from position (2i^+k^) meter to position (4i^+3j^​−k^) meter. The work done by the force on the particle is