A particle of mass 0.5kg is displaced from position r→1(2,3,1) to r→2(4,3,2) by applying a force of magnitude 30N which is acting along (iˆ+jˆ+kˆ). The work done by the force is 1) to r→2(4 2) by applying a force of magnitude 30N which is acting along (iˆ+jˆ+kˆ). The work done by the force is 3% A particle of mass 0.5kg is displaced from position r→1(2 October 19, 2020 Category: Arihant Physics by D.C Pandey , Chapter 6 - Work, Energy and Power , Volume 2 , Facebook Messenger WhatsApp Share this:TwitterFacebook Related