A particle of mass 0.50 kg executes a simple harmonic motion under a force F = -(50 N/m)x. If it crosses the centre of oscillation with a speed of 10 m/s, find the amplitude of motion. A particle of mass 0.50 kg executes a simple harmonic motion under a force F = -(50 N/m)x. If it crosses the centre of oscillation with a speed of 10 m/s find the amplitude of motion. September 3, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) , Facebook Messenger WhatsApp Share this:TwitterFacebook Related