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Sahay Sir > Question Answers > Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) > A particle of charge q and mass m moving with a velocity v along x−axis enters the region x>0 with uniform magnetic field B along the k ^ direction. The particle will penetrate in this region in the x−direction up to a distance d equal to

A particle of charge q and mass m moving with a velocity v along x−axis enters the region x>0 with uniform magnetic field B along the k ^ direction. The particle will penetrate in this region in the x−direction up to a distance d equal to

A proton of mass m and charge +e is moving in a circular orbit in a magnetic fielg with energy 1 Me V. What should be the energy of alpha particle ( mass = 4 m and charge = + 2e ) so that it can revolve in the path of same radius?