A particle moves in a circular path such that its speed 1v varies with distance s as v = sqrt(s), where prop is a positive constant. Find the acceleration of the particle after traversing a distance s. A particle moves in a circular path such that its speed 1v varies with distance s as v = sqrt(s) where prop is a positive constant. Find the acceleration of the particle after traversing a distance s. August 28, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) , Facebook Messenger WhatsApp Share this:TwitterFacebook Related