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Sahay Sir > Question Answers > Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) > A particle moves from the point (2.0 i+40 j^)m, at t=0, with an initial velocity (5.0 i^+4.0 j^)ms −1 . It is acted upon by a constant force which produces a constant acceleration (4.0^+4.0 j^ )ms−2 . What is the distance of the particle from the origin at time 2 s?

A particle moves from the point (2.0 i+40 j^)m, at t=0, with an initial velocity (5.0 i^+4.0 j^)ms −1 . It is acted upon by a constant force which produces a constant acceleration (4.0^+4.0 j^ )ms−2 . What is the distance of the particle from the origin at time 2 s?

A particle moves from the point (2.0 i+40 j^)m At t=0 the angle that the pendulum makes with the vertical is : (take g=10 m/s 2 ). The bob of a simple pendulum has mass 2g and a charge of 5.0μC. It is at rest in a uniform horizontal electric field of intensity 2000 V/m. At equilibrium