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Sahay Sir > Question Answers > Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) > A particle (mass = 6.0 mg) moves with a speed of 4.0 km/s in a direction that makes an angle of 37 ∘ above the positive x axis in the xy plane. At the instant it enters a magnetic field of (5.0 ^ i )mT it experiences an acceleration of (8.0 ^ k ) m / s 2 . What is the charge of the particle?

A particle (mass = 6.0 mg) moves with a speed of 4.0 km/s in a direction that makes an angle of 37 ∘ above the positive x axis in the xy plane. At the instant it enters a magnetic field of (5.0 ^ i )mT it experiences an acceleration of (8.0 ^ k ) m / s 2 . What is the charge of the particle?

A proton of charge e and mass m enters a uniform magnetic field B= B i ^ with an initial velocity v =v x ​i ^+v y j ^. Find an expression in unit-vector notation for its velocity at time t. In figure