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Sahay Sir > Question Answers > Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) > A particle located in a one-dimensional potential field has its potential energy function as U (x) a/x^4 – b/x^2, where a and b are positive constants. The position of equilibrium x

A particle located in a one-dimensional potential field has its potential energy function as U (x) a/x^4 – b/x^2, where a and b are positive constants. The position of equilibrium x

A particle located in a one-dimensional potential field has its potential energy function as U (x) a/x^4 - b/x^2 where a and b are positive constants. The position of equilibrium x