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Sahay Sir > Question Answers > JEE Mains Physics 2002-2019 Solved Video Solutions > Practice Set 1 > A particle is projected with velocity v0 along x-axis. A damping force is acting on the particle which is proportional to the square of the distance from the origin i.e., ma = –ax^2. The distance at which the particle stops :

A particle is projected with velocity v0 along x-axis. A damping force is acting on the particle which is proportional to the square of the distance from the origin i.e., ma = –ax^2. The distance at which the particle stops :

A particle is projected with velocity v0 along x-axis. A damping force is acting on the particle which is proportional to the square of the distance from the origin i.e. ma = –ax^2. The distance at which the particle stops :