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Sahay Sir > Question Answers > JEE Mains Physics 2002-2019 Solved Video Solutions > Chapter 3 - Laws of Motion > A particle is moving in a circular path of radius a under the action of an attractive potential U=−k2/r^2. Its total energy is :

A particle is moving in a circular path of radius a under the action of an attractive potential U=−k2/r^2. Its total energy is :

A particle is moving in a circular path of radius a under the action of an attractive potential U=−k2/r^2. Its total energy is :