A particle is executing SHM under the action of force whose maximum magnitude is 50 N. Find the magnitude of force acting on the particle at the time when its energy is half kinetic and half potential. A particle of mass 0.50 kg executes a simple harmonic motion under a force F = -(50 N/m)x. If it crosses the centre of oscillation with a speed of 10 m/s find the amplitude of motion. September 3, 2020 Category: Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) , Facebook Messenger WhatsApp Share this:TwitterFacebook Related