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Sahay Sir > Question Answers > Cengage JEE Mains Physics by B.M Sharma > Chapter 15 - Oscillation and SHM > A particle free to move along the x-axis has potential energy given by U(x) = k[1−exp(−x^2 )] for−∞≤ x ≤+∞, where k is a positive constant of appropriate dimensions. Then:

A particle free to move along the x-axis has potential energy given by U(x) = k[1−exp(−x^2 )] for−∞≤ x ≤+∞, where k is a positive constant of appropriate dimensions. Then:

A particle free to move along the x-axis has potential energy given by U(x) = k[1−exp(−x^2 )] for−∞≤ x ≤+∞ where k is a positive constant of appropriate dimensions. Then: