A parachutist drops first freely from an aeroplane for 10 s and then his parachute opens out. Now he descends with a net retardation of 2.5 ms^−2. If he bails out of the plane at a height of 2495 m and g = 10 ms^−2, his velocity on reaching the ground will be

- September 5, 2020
- Category: Cengage JEE Mains Physics by B.M Sharma , Chapter 3 - Motion in One Dimension ,
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A body is project at t= 0 with a velocity 10ms−1 at an angle of 60∘ with the horizontal .The radius of curvature of its trajectory at t=1 s is R. Neglecting air resistance and taking acceleration due to gravity g=10 ms−2, the value of R is :
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