A nucleus with Z=92 emits the following in a sequence; α,α,β−,β−,α,α,α,α,β−,β−,α,β+,β+,α. The Z of the resulting nucleus is A nucleus with Z=92 emits the following in a sequence; α α α. The Z of the resulting nucleus is β+ β− November 28, 2020 Category: Chapter 18 - Atoms and Nuclei , JEE Mains Physics 2002-2019 Solved Video Solutions , Facebook Messenger WhatsApp Share this:TwitterFacebook Related