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Sahay Sir > Question Answers > JEE Mains Physics 2002-2019 Solved Video Solutions > Chapter 18 - Atoms and Nuclei > A nucleus at rest undergoes alpha decay emitting an alpha particle of de Broglie wavelength lemba = 5.76 * 10^-15 m. If the mass of the daughter nucleus is 223.610 amu and that of the alpha particle is 4.002 amu, determine the total kinetic energy in a final state. Hence obtain the mass of the parent nucleus in amu.

A nucleus at rest undergoes alpha decay emitting an alpha particle of de Broglie wavelength lemba = 5.76 * 10^-15 m. If the mass of the daughter nucleus is 223.610 amu and that of the alpha particle is 4.002 amu, determine the total kinetic energy in a final state. Hence obtain the mass of the parent nucleus in amu.

Beta rays emitted by a radioactive material are.