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Sahay Sir > Question Answers > Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) > A metallic disc is being heated. Its area A ( in m^2) at any time t ( in second) is given by A = 5t^2 + 4t + 8. Calculate the rate of increase in area at t = 3s.

A metallic disc is being heated. Its area A ( in m^2) at any time t ( in second) is given by A = 5t^2 + 4t + 8. Calculate the rate of increase in area at t = 3s.

A metallic disc is being heated. Its area A ( in m^2) at any time t ( in second) is given by A = 5t^2 + 4t + 8. Calculate the rate of increase in area at t = 3s.