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Sahay Sir > Question Answers > MTG NEET Physics > Part 1 > Chapter 3 - Motion in One Dimension > A man runs at a speed of 4.0m/s to overtake a standing bus. When he is 6.0m behind the door (at t=0), then bus moves forward and continues with a constant acceleration of 1.2m/s^2. The man shall access the door at time t equal to:

A man runs at a speed of 4.0m/s to overtake a standing bus. When he is 6.0m behind the door (at t=0), then bus moves forward and continues with a constant acceleration of 1.2m/s^2. The man shall access the door at time t equal to:

A man runs at a speed of 4.0m/s to overtake a standing bus. When he is 6.0m behind the door (at t=0) then bus moves forward and continues with a constant acceleration of 1.2m/s^2. The man shall access the door at time t equal to: