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Sahay Sir > Question Answers > Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) > A man of mass 100 kg stands at the rim of a turntable of radius 2 m and moment of interia 4000 kg m^2 mounted on a vertical frictionless shaft at its centre. THe whole system is initially at rest. The man now walks along the outer edge of the turnable with a velocity of 1 m/s relative to the earth.

A man of mass 100 kg stands at the rim of a turntable of radius 2 m and moment of interia 4000 kg m^2 mounted on a vertical frictionless shaft at its centre. THe whole system is initially at rest. The man now walks along the outer edge of the turnable with a velocity of 1 m/s relative to the earth.

A disk with moment of inertia I1 rotates about a frictionless drops onto the first disk. Because of friction between the surfaces the two eventually reach the same angular speed ω f. Calculate ω f. this one having moment of inertia I2 and initially not rotating vertical axle with angular speed ω i. A second disk