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Sahay Sir > Question Answers > Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) > A loop of wire has the shape shown in the drawing. The top part of the wire is bent into a semicircle of radius r = 0.20 m. The normal to the plane of the loop is parallel to a constant magnetic field (theta = 0 degree) of magnitude 0.75 T. What is the change in the magnetic flux ( delta phi) that passes through the loop when, starting with the position shown in the drawing, the semicircle is rotated through half a revolution?

A loop of wire has the shape shown in the drawing. The top part of the wire is bent into a semicircle of radius r = 0.20 m. The normal to the plane of the loop is parallel to a constant magnetic field (theta = 0 degree) of magnitude 0.75 T. What is the change in the magnetic flux ( delta phi) that passes through the loop when, starting with the position shown in the drawing, the semicircle is rotated through half a revolution?

A long solenoid with radius 2 cm carries a current of 2 A. The solenoid is 70 cm long and is composed of 300 turns of wire. Assuming ideal solenoid model as shown in the figure. What is the total flux of the earth's magnetic field associated with an area S At a given place horizontal and vertical components of the earth's magnetic field BH and BV are along X and Y-axes calculate the flux linked with a circular surface if (a) it has a radius of 1cm and is perpendicular to the axis of the solenoid: (i) inside if the area S is in the (i) XY-plane (ii) YZ-plane (iii) X-Z plane. respectively