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Sahay Sir > Question Answers > Cengage NEET by C.P Singh > Part 1 > Chapter 22 - Heat Transfer > A liquid in a beaker has temperature θ at time t and θ0 is temperature of surroundings, then according to Newton’s law of cooling, correct graph between loge (θ−θ 0 ) and t is :

A liquid in a beaker has temperature θ at time t and θ0 is temperature of surroundings, then according to Newton’s law of cooling, correct graph between loge (θ−θ 0 ) and t is :

September 10, 2021
Category: Cengage NEET by C.P Singh , Chapter 22 - Heat Transfer , Part 1 ,

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A liquid in a beaker has temperature θ at time t and θ0 is temperature of surroundings, then according to Newton’s law of cooling, correct graph between loge (θ−θ 0 ​) and t is :

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A liquid in a beaker has temperature θ at time t and θ0 is temperature of surroundings, then according to Newton’s law of cooling, correct graph between loge (θ−θ 0 ) and t is :