A juggler keeps on moving four balls in air throwing the balls after regular intervals. When one ball leaves his hand (speed = 20 ms^−1), the position of other balls (height in metre) will be : (Take g = 10 ms^−2)

A juggler keeps on moving four balls in air throwing the balls after regular intervals. When one ball leaves his hand (speed = 20 m/s), the position of other balls (height in meter) will be

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A juggler maintains four balls in motion, making each to them to rise a height of 20 m from his hand. What time interval should he maintain, for the proper distance between them.

A person throws balls into air vertically upward in regular intervals of time of one second. The next ball is thrown when the velocity of the ball thrown earlier becomes zero. The height to which the balls rise is (Assume, g=10ms^−2)