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Sahay Sir > Question Answers > N Awasthi Physical Chemistry > Chapter 2 - Atomic Structure (Level 1 and Level 2) > A hydrogen like species (atomic number Z) is present in a higher excited state of quantum number n. This excited atom can make a transition to the first excited state by successive emission of two photons of energies 10.20eV and 17.0eV respectively. Alternatively, the atom from the same excited state can make a transition to the second excited state by successive emission of two photons of energy 4.25eV and 5.95eV respectively. Determine the value of Z.

A hydrogen like species (atomic number Z) is present in a higher excited state of quantum number n. This excited atom can make a transition to the first excited state by successive emission of two photons of energies 10.20eV and 17.0eV respectively. Alternatively, the atom from the same excited state can make a transition to the second excited state by successive emission of two photons of energy 4.25eV and 5.95eV respectively. Determine the value of Z.

For a 3s−orbital value of v is given by following relation: ψ(3s)= 9 root3/1 ( a0/1)^3/2 (6−6σ+σ^2 )e −σ/2 ;whereσ = 3a0/2r.Z ​ What is the maximum radial distance of the node from the nucleus?