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Sahay Sir > Question Answers > Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) > A hydrogen like atom of atomic number Z is in an excited state of quantum number 2n.It can emit a maximum energy photon of 204 eV. if it makes a transiton to quantum state n, then an photon of energy 40.8 eV is emitted.The value of n will be

A hydrogen like atom of atomic number Z is in an excited state of quantum number 2n.It can emit a maximum energy photon of 204 eV. if it makes a transiton to quantum state n, then an photon of energy 40.8 eV is emitted.The value of n will be

A hydrogen like atom of atomic number Z is in an excited state of quantum number 2n.It can emit a maximum energy photon of 204 eV. if it makes a transiton to quantum state n then an photon of energy 40.8 eV is emitted.The value of n will be