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Sahay Sir > Question Answers > Uncategorised (JEE Advanced Physics by BM Sharma + GMP Solutions) > A hot black body emits the energy at the rate of 16 Jm^−2s^−1 and its most intense radiation corresponds to 20000Å. When the temprerature of this body is further increased and its most intense radiation corresponds to 10000Å, then find the value of energy radiated in Jm^−2s^−1.

A hot black body emits the energy at the rate of 16 Jm^−2s^−1 and its most intense radiation corresponds to 20000Å. When the temprerature of this body is further increased and its most intense radiation corresponds to 10000Å, then find the value of energy radiated in Jm^−2s^−1.

A hot body placed in air is cooled down according to Newton's law of cooling find the time in which the body will loss half the maximum heat it can lose. the rate of decrease of temperature being k times the temperature difference from the surrounding. Starting from t=0